Problem
Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
Given a string s containing just the characters ‘(‘, ‘)’, ‘{‘, ‘}’, ‘[‘ and ‘]’, determine if the input string is valid.
An input string is valid if:
Open brackets must be closed by the same type of brackets.
Open brackets must be closed in the correct order.
Example
Example 1:
Input: s = "()"
Output: true
Example 2:
Input: s = "()[]{}"
Output: true
Example 3:
Input: s = "(]"
Output: false
Example 4:
Input: s = "([)]"
Output: false
Example 5:
Input: s = "{[]}"
Output: true
Solution- Kotlin
fun main(args:Array<String>){
var result= isValid("{[]}")
printResult("Remove Element ",result.toString())
}
fun isValid(s: String): Boolean {
var stack=Stack<String>()
s.forEach {
when(it.toString()){
"{"->stack.push("}")
"("->stack.push(")")
"["->stack.push("]")
else-> {
if(stack.isEmpty()||stack.pop()!=it.toString()){
return false
}
}
}
}
return stack.isEmpty()
}